Find the value of x in OQ. 5x-6
2x+9
Need help with this question asap!!

Answer:
[tex]\huge\boxed{\sf x = 5}[/tex]
Step-by-step explanation:
Since, the chord is being bisected by the diameter (being divided into two equal parts). Hence,
5x - 6 = 2x + 9
5x - 2x = 9 + 6
3x = 15
Divide both sides by 3
x = 15 / 3
x = 5
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!