Answer:
See Explanation
Step-by-step explanation:
The question is incomplete as the image that illustrates the scenario is not given.
However, I can deduce that the question is about a right-angled triangle.
So, I will give a general explanation on how to find each of the side of the triangle, given a side and an angle.
For triangle A (solve for b)
Using cosine formula.
[tex]\cos \theta = \frac{Adjacent}{Hypotenuse}[/tex]
[tex]\cos 60= \frac{5}{b}[/tex]
Make b the subject
[tex]b= \frac{5}{\cos 60}[/tex]
For triangle B (solve for b)
Using cosine formula.
[tex]\sin \theta = \frac{Opposite}{Hypotenuse}[/tex]
[tex]\sin 60= \frac{b}{5}[/tex]
Make b the subject
[tex]b = 5\sin 60[/tex]
For triangle C (solve for b)
Using cosine formula.
[tex]\tan \theta = \frac{Opposite}{Adjacent}[/tex]
[tex]\tan 60= \frac{b}{5}[/tex]
Make b the subject
[tex]b = 5\tan 60[/tex]
