Answer:
0.99 μmol/L
Explanation:
From the question given above, the following data were obtained:
Volume of stock solution (V₁) = 20 mL
Concentration of stock solution (C₁) = 18.8 μmol/L
Volume of diluted solution (V₂) = 380 mL
Concentration of diluted solution (C₂) =?
The concentration of the diluted solution can be obtained as follow:
C₁V₁ = C₂V₂
18.8 × 20 = C₂ × 380
376 = C₂ × 380
Divide both side by 380
C₂ = 376 / 380
C₂ = 0.99 μmol/L
Therefore, the concentration of the diluted solution the chemist is working on is 0.99 μmol/L
