greenmochi greenmochi

19-04-2021
Chemistry

contestada

find the empirical formula for
42.05g of nitrogen, 95.95 of oxygen

and
7.33g of lanthanum, 2.96g of oxygen

Respuesta :

kimchiboy03 kimchiboy03

19-04-2021

Answer:

[tex]NO_2[/tex] and [tex]La_2O_7[/tex]

Explanation:

Nitrogen:

[tex]\frac{42.05}{14}=3[/tex]

Oxygen:

[tex]\frac{95.95}{16}=6[/tex]

Ratio:

[tex]3:6=1:2[/tex]

So empirical formula becomes [tex]NO_2[/tex]

-----

Lanthanum:

[tex]\frac{7.33}{139}=0.0527[/tex]

Oxygen:

[tex]\frac{2.96}{16}=0.185[/tex]

Ratio:

[tex]0.0527:0.185=1:3.5=2:7[/tex]

So empirical formula becomes [tex]La_2O_7[/tex]

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