Answer:
All three designs will hold he same amount of chocolate (60 cubic centimeters). So, the manager is wrong.
Step-by-step explanation:
Let's find the volume of each design.
For Design A, the cross section is a rectangle rectangle measured 3 cm by 2 cm.
Therefore, the area of the cross section is:
[tex]A_1=3(2)=6\text{ cm}^2[/tex]
Since the height is 10 cm, the total volume of Design A is:
[tex]V_1=10(6)=60\text{ cm}^2[/tex]
For Design B, the cross section is also a rectangle measuring 3 cm by 2 cm.
So, the area of the cross section is:
[tex]A_2=3(2)=6\text{ cm}^2[/tex]
And the height is still 10 cm. So, the total volume of Design B is:
[tex]V_2=6(10)=60\text{ cm}^3[/tex]
Note that we use the vertical height, and not the slant height. If this seems confusing, imagine each layer being a cracker. If 10 crackers were laid on top of each other perfectly, that is Design A. However, if we were to move each cracker to the right a bit, that is Design B. The volume of both cases are the same.
For Design C, the cross section is a triangle with a base length of 6 cm and a height of 2 cm.
So, the area of the cross section is:
[tex]\displaystyle A_3=\frac{1}{2}(2)(6)=6[/tex]
And since the height is 10 cm, the volume of Design C is:
[tex]V_3=6(10)=60\text{ cm}^3[/tex]
Therefore, as we can see, all three designs will hold he same amount of chocolate. So, the manager is wrong.
