Answer:
E = 7200 J = 7.2 KJ
Explanation:
The electric field due to a sphere is similar to the electric field due to a point charge. It is calculated by the use of the following formula:
[tex]E = \frac{kq}{r^2}\\[/tex]
where,
E = Electric Field = ?
k = Coulomb Constant = 9 x 10⁹ Nm²/C²
q = charge on sphere = 2 μC = 2 x 10⁻⁶ C
r = distance from the center of the sphere to the location = 5 cm = 0.05 m
Therefore,
[tex]E = \frac{(9\ x\ 10^9\ Nm^2/C^2)(2\ x\ 10^{-6}\ C)}{(0.05\ m)^2}[/tex]
E = 7200 J = 7.2 KJ
