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The bottom edge of a 16-foot long cantilever is given by the equation y = 2Vx, where y is the distance the

bottom edge is from ground height, in feet.

y

(a) What is the value of b, the height of the

cantilever, in feet?

b

T

y=2&x

b) To the nearest tenth of a foot, what is the

thickness, T, of the cantilever at x =6 feet?

Respuesta :

MrRoyal

Answer:

[tex](a)\ b = 8[/tex]

[tex](b)\ T = 3.1[/tex]

Step-by-step explanation:

Given

[tex]y = 2\sqrt x[/tex]

See attachment

Solving (a): Find b

At point b, [tex]x = 16[/tex]

So, the value of b is:

[tex]b = 2 * \sqrt{16[/tex]

[tex]b = 2 * 4[/tex]

[tex]b = 8[/tex]

Solving (b): Find T

First, we calculate the value of y at point T

[tex]y = 2\sqrt x[/tex]

At point T, [tex]x = 6[/tex]

So:

[tex]y = 2 * \sqrt 6[/tex]

[tex]y = 2 * 2.45[/tex]

[tex]y = 4.9[/tex]

To calculate T, we subtract the calculated height (y) from the value of b

[tex]T =b - y[/tex]

[tex]T = 8 - 4.9[/tex]

[tex]T = 3.1[/tex]

Ver imagen MrRoyal

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