The following equation is true for all real values of k for which the expression on the left is defined, and A
is a polynomial expression.
6k2 – 36k k2 + 12k + 36
А
k2 - 36
1
What is A?

The following equation is true for all real values of k for which the expression on the left is defined and A is a polynomial expression 6k2 36k k2 12k 36 А k2 class=

Respuesta :

Answer:

A = 6k(k + 6)

Step-by-step explanation:

We have to solve the given equation for the value of A,

[tex]\frac{6k^2-36k}{A}.\frac{k^2+12k+36}{k^2-36}=1[/tex]

[tex]\frac{(6k^2-36k)(k^2+12k+36)}{A(k^2-36)}=1[/tex]

(6k² - 36k)(k² + 12k + 36) = A(k² -36)

6k(k - 6)(k + 6)² = A(k - 6)(k + 6)

A = [tex]\frac{6k(k-6)(k+6)^2}{(k-6)(k+6)}[/tex]

A = 6k(k + 6)

Therefore, value of A is 6k(k + 6).

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