Answer:
3 units
Step-by-step explanation:
Equation of the circle is:
[tex] (x+3)^2 +(y+1)^2=r^2 [/tex]
[tex] \therefore [x-(-3)] ^2 +[(y-(-1)] ^2=r^2 [/tex]
Equating it with
[tex] (x-h)^2 +(y-k)^2=r^2 [/tex]
We find: h = - 3 & k = - 1
Center of the circle (C) = (-3, - 1)
Since, the point (-3, 2) lies on the circle, therefore radius of the circle wii be equal to the distance between the center of the circle (-3, - 1) and the point (-3, 2) which is on the circle.
Therefore,
[tex] r = \sqrt{[-3-(-3)]^2 +[2-(-1)]^2} [/tex]
[tex] r = \sqrt{[-3+3]^2 +[2+1]^2} [/tex]
[tex] r = \sqrt{[0]^2 +[3]^2} [/tex]
[tex] r = \sqrt{0 +9} [/tex]
[tex] r = \sqrt{9} [/tex]
[tex] r = 3\: units [/tex]
