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At some temperature for the equilibrium PX3(g) + X2(g) # PX5(g) the equilibrium constant is 0.74. At the same temperature the equilibrium constant for PX5(9) + PX3(g) X2(g) is​

Respuesta :

Answer: The equilibrium constant for [tex]PX_5(g)\rightarrow PX_3(g)+X_2(g)[/tex] is 1.35

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as [tex]K_c[/tex]  

For the given chemical reaction:

[tex]PX_3(g)+X_2(g)\rightarrow PX_5(g)[/tex]

The expression for [tex]K_c[/tex] is written as:

[tex]K_c=\frac{[PX_5]^1}{[PX_3]^1[X_2]^1}[/tex]

[tex]0.74=\frac{[PX_5]^1}{[PX_3]^1[X_2]^1}[/tex]

For the reverse chemical reaction:

[tex]PX_5(g)\rightarrow PX_3(g)+X_2(g)[/tex]

The expression for [tex]K_c'[/tex] is written as:

[tex]K_c'=\frac{[PX_3]^1[X_2]^1}{[PX_5]^1}[/tex]

[tex]K_c'=\frac{1}{K_c}=\frac{1}{0.74}=1.35[/tex]

The equilibrium constant for [tex]PX_5(g)\rightarrow PX_3(g)+X_2(g)[/tex] is 1.35