Answer: 2755.2 g of [tex]Fe[/tex] will be produced from 24.6 mol of haematite.
Explanation:
The balanced chemical equation is:
[tex]Fe_2O_3+3CO\rightarrow 2Fe+3CO_2[/tex]
According to stoichiometry :
1 mole of [tex]Fe_2O_3[/tex] produce = 2 moles of [tex]Fe[/tex]
Thus 24.6 moles of [tex]Fe_2O_3[/tex] will produce=[tex]\frac{2}{1}\times 24.6=49.2moles[/tex] of [tex]Fe[/tex]
Mass of [tex]Fe=moles\times {\text {Molar mass}}=49.2moles\times 56g/mol=2755.2g[/tex]
Thus 2755.2 g of [tex]Fe[/tex] will be produced from 24.6 mol of haematite.
