Answer:
F = 4117.64
Explanation:
First, we will calculate the acceleration of the hand, by using the third equation of motion:
[tex]2as = v_f^2 - v_i^2\\[/tex]
where,
a = acceleration = ?
s = distance covered = compression = 8.5 cm = 0.085 m
vf = final speed = 0 m/s
vi = iniial speed = 10 m/s
Therefore,
[tex]2a(0.085\ m) = (0\ m/s)^2-(10\ m/s)^2\\a = - 588.23\ m/s^2[/tex]
negative sign hows deceleration.
Now, we will calculate the force exerted by the hand:
[tex]F = ma = (7\ kg)(588.23\ m/s^2)\\[/tex]
F = 4117.64 N
