Answer:
[tex]P = 103867260[/tex] atm
Explanation:
The pressure at the bottom of any liquid column is equal to product of density of the liquid , gravitational acceleration constant (g) and height of the water column
Thus, [tex]P = \rho*g*h[/tex]
Substituting the given values, we get -
[tex]P = 1029[/tex] kg/m3 [tex]* 9.8[/tex] m/s^2 [tex]*10.3 *1000[/tex] meters
[tex]P = 103867260[/tex] atm