Answer:
Step-by-step explanation:
Given that:
the differential equations:
[tex]\dfrac{dx}{dt}= x+y = 1 \\ \\ \dfrac{dy}{dt}= 1-x^2+y^2[/tex]
For x-nullcline;
[tex]\implies \dfrac{dx}{dt} =0 \\ \\ \implies x+y-1[/tex]
From the image attached below, the sketch of the x-nullcline was carefully drawn and the regions were identified.
So, x-increases at the time when [tex]\dfrac{dx}{dt}>0[/tex]
[tex]\implies x+y -1 >0[/tex]
Thus, the solution move towards the right for x+y>1