Respuesta :
Answer:
Perimeter of pizza slice = 27.85 inches (Approx.)
Step-by-step explanation:
Given:
Diameter of pizza = 20 inches
So,
Radius of pizza slice = Diameter of pizza / 2
Radius of pizza slice = 20 / 2 = 10 inches
∠IPZ = 45°
Find:
Perimeter of pizza slice
Computation:
Perimeter of pizza slice = 2[Radius of pizza slice] + [θ/360][2πr]
Perimeter of pizza slice = 2[10] + [45/360][(2)(22/7)(10)]
Perimeter of pizza slice = 20 + [0.125][(2)(3.14)(10)]
Perimeter of pizza slice = 20 + [0.125][62.8]
Perimeter of pizza slice = 20 + 7.85
Perimeter of pizza slice = 27.85 inches (Approx.)
The perimeter of the slice of the pizza that is eaten, measured in inches, for the considered case, is 31.9635 inches.
How to find the relation between angle subtended by the arc, the radius and the arc length?
[tex]2\pi^c = 360^\circ = \text{Full circumference}[/tex]
The superscript 'c' shows angle measured is in radians.
If radius of the circle is of r units, then:
[tex]1^c \: \rm covers \: \dfrac{circumference}{2\pi} = \dfrac{2\pi r}{2\pi} = r\\\\or\\\\\theta^c \: covers \:\:\: r \times \theta \: \rm \text{units of arc}[/tex]
For this case, we're given that:
- Angle m∠IPZ=45°.
- Diameter of the circular pizza = 20 inches
Not using the above formula, but the concept, we know that:
- 360° covers full arc, which is [tex]2\pi r[/tex] inch lengthed long.
- 45° is 360°/8, so it will cover [tex]2\pi r/8[/tex] inch long arc (the arc IZ).
Since diameter of pizza = 20 inches, its radius r = 10 inches.
Thus, the length of the arc IZ = [tex]\dfrac{2 \times \pi \times 10}{8} \approx 1.9635 \: \rm inches.[/tex]
Perimeter of the slice of the pizza eaten = sum of the length of its boundaries = Length of arc IZ + length of line IP + length of line ZP
Since line IP and ZP are radius, thus:
Perimeter of the slice of the pizza eaten ≈ 1.9635 + 10 + 10 = 31.9635 inches.
Thus, the perimeter of the slice of the pizza that is eaten, measured in inches, for the considered case, is 31.9635 inches.
Learn more about angle, arc length relation here:
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