Answer:
[tex]x = 0[/tex]
Step-by-step explanation:
Given
[tex](x_1,y_1) = (3,0)[/tex]
[tex](x_2,y_2) = (-3,0)[/tex]
Required
The equation of the perpendicular bisector.
First, calculate the midpoint of the given endpoints
[tex](x,y) = 0.5(x_1 + x_2, y_1 + y_2)[/tex]
[tex](x,y) = 0.5(3-3, 0+ 0)[/tex]
[tex](x,y) = 0.5(0, 0)[/tex]
Open bracket
[tex](x,y) = (0.5*0, 0.5*0)[/tex]
[tex](x,y) = (0, 0)[/tex]
Next, determine the slope of the given endpoints.
[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
[tex]m = \frac{0 - 0}{-3- 3}[/tex]
[tex]m = \frac{0}{-6}[/tex]
[tex]m = 0[/tex]
Next, calculate the slope of the perpendicular bisector.
When two lines are perpendicular, the relationship between them is:
[tex]m_2 = -\frac{1}{m_1}[/tex]
In this case:
[tex]m = m_1 = 0[/tex]
So:
[tex]m_2 = -\frac{1}{0}[/tex]
[tex]m_2 = unde\ fined[/tex]
Since the slope is [tex]unde\ fined[/tex], the equation is:
[tex]x = a[/tex]
Where:
[tex](x,y) = (a,b)[/tex]
Recall that:
[tex](x,y) = (0, 0)[/tex]
So:
[tex]a = 0[/tex]
Hence, the equation is:
[tex]x = 0[/tex]
