Answer:
[tex] \rm\displaystyle \: A _{ \text{ total}} = 212 [/tex]
Step-by-step explanation:
Prefer the attachment
so we have 3 rectangle
recall that,
[tex] \displaystyle \: A _{ \text{ rect}} = l \times w[/tex]
rectangle-1:
the width of the rectangle is 10m
and the length is 12+5=17m
so the area is
[tex] \displaystyle \: A _{ \text{ rect - 1}} = 17 \times 10[/tex]
[tex] \displaystyle \: A _{ \text{ rect - 1}} =170 \: {m}^{2} [/tex]
rectangle-2:
the length is 9 m
the width is 3 m
so the area is
[tex] \displaystyle \: A _{ \text{ rect - 2}} = 9 \times3[/tex]
[tex] \displaystyle \: A _{ \text{ rect - 2}} = 27 \: {m}^{2} [/tex]
rectangle-3:
the length is 5m
the width is 3m
so the area is
[tex] \displaystyle \: A _{ \text{ rect - 3}} = 5 \times 3[/tex]
[tex] \displaystyle \: A _{ \text{ rect - 3}} = 15 {m}^{2} [/tex]
total area:
[tex] \rm\displaystyle \: A _{ \text{ total}} =170 \: {m}^{2} + {27m}^{2} + {15m}^{2} [/tex]
[tex] \rm\displaystyle \: A _{ \text{ total}} = 212 {m}^{2} [/tex]
