Answer:
The ordered pair is: [tex](\frac{7\sqrt{3}}{2},\frac{5\sqrt{3}}{2})[/tex]
Step-by-step explanation:
We are given the following plane curve:
[tex]x = 7 \cos{t}[/tex]
[tex]y = 5 \cos{t}[/tex]
Ordered pair for a value of t:
We find (x,y) for these values of t. So, when [tex]t = \frac{\pi}{6}[/tex]
[tex]x = 7 \cos{\frac{\pi}{6}} = 7\frac{\sqrt{3}}{2} = \frac{7\sqrt{3}}{2}[/tex]
[tex]y = 5 \cos{\frac{\pi}{6}} = 5\frac{\sqrt{3}}{2} = \frac{5\sqrt{3}}{2}[/tex]
The ordered pair is: [tex](\frac{7\sqrt{3}}{2},\frac{5\sqrt{3}}{2})[/tex]
