Answer:
[tex]P_2=3120mmHg[/tex]
Explanation:
Hello there!
In this case, according to the Gay-Lussac's law, which sets up the pressure-volume behavior as a directly proportional relationship:
[tex]P_1V_1=P_2V_2[/tex]
Thus, since we are asked for the final pressure, P2, we obtain:
[tex]P_2=\frac{P_1V_1}{V_2} =\frac{780mmHg*100.0mL}{25.0mL}\\\\P_2=3120mmHg[/tex]
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