contestada


How many grams of KI are needed to prepare 2,000. grams of an aqueous solution
containing 25 parts per million (ppm) of solute?

Respuesta :

Answer:

[tex]m_{solute}=0.05g[/tex]

Explanation:

Hello there!

In this case, according to the equation for the calculation of the parts per million:

[tex]ppm=\frac{m_{solute}}{m_{solution}} *1x10^6[/tex]

It is possible to solve for the mass of KI (solute) as shown below:

[tex]m_{solute}=\frac{ppm*m_{solution}}{1x10^6}[/tex]

Thus, we plug in to obtain:

[tex]m_{solute}=\frac{25*2,000g}{1x10^6} \\\\m_{solute}=0.05g[/tex]

Best regards!