Answer:
"490 grams" would be the correct solution.
Step-by-step explanation:
The given values are:
Half time,
T = 35 days
Total time,
t = 105 days
As we know,
⇒ [tex]A=A_o(\frac{1}{2} )^{\frac{t}{T} }[/tex]
On substituting the values, we get
⇒ [tex]=3920\times (\frac{1}{2})^{\frac{105}{35} }[/tex]
⇒ [tex]=3920\times (0.5)^3[/tex]
⇒ [tex]=3920\times 0.125[/tex]
⇒ [tex]=490 \ grams[/tex]
