Answer:
The reasonable prediction for successful rolls is 4.
Step-by-step explanation:
Assuming the rolling cube is a fair 6 sided cube, so the probability of success of one roll is given as
[tex]P(Success)=\dfrac{Number\ of\ successful\ events}{Number\ of\ total\ events}[/tex]
[tex]P(Success)=\dfrac{1}{6}[/tex]
The total success is given as
[tex]P(Total\ Success)=P(Success)\times Number\ of\ events[/tex]
For 24 rolls it is given as
[tex]P(Total\ Success)=P(Success)\times Number\ of\ events\\P(Total\ Success)=\dfrac{1}{6}\times 24\\P(Total\ Success)=4[/tex]
So the reasonable prediction for successful rolls is 4.
