No, the facility dose not have the exact pattern as the recent report at the 10% level.
To determine if the Facility have the same pattern,
By using Chi squared test for Goodness of fit state the hypothesis
[tex]$H_{0}[/tex] : μ = same pattern
[tex]$H_{a}[/tex] : μ ≠ same pattern
Expected frequency (E) = proportion [tex]*[/tex] summation of frequency
summation of frequency = 1000
degree of freedom [tex]= 7 - 1 = 6[/tex]
Calculate the expected frequency (E) ,(O-E)²/E.
Given that the observed frequency and expected proportion exists given
For Monday
expected frequency = proportion [tex]*[/tex] frequency = 0.1 [tex]*[/tex] 1000 = 100
(O-E)²/E. = ( 120 - 100 )² / 100 = 4.0.
observed frequency (O), expected frequency (E)
For Tuesday
E = 0.1 [tex]*[/tex] 1000 = 100
(O-E)²/E = ( 130 - 100 )² / 100 = 9.0
For Wednesday through Sunday
Then perform Chi-squared test
X² = Σ(O-E)²/E = 63.642
∝ = 0.1
df = 6
hence P-value = 0.000 ( = chi sq dist rt(test-stat,df)
since P-value < ∝ ; we will fail to reject Ha hence we reject [tex]$H_{0}[/tex].
To learn more about Chi squared test
https://brainly.com/question/23537567
#SPJ2
