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Answer the question below. Use the rubric in the materials for help if needed.
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Describe the process used to determine how many atoms of each element are in 2Ca3(PO4)2. Show all
your work.

Respuesta :

sebassandin

Answer:

Six atoms of calcium, four of phosphorous and sixteen of oxygen for a total of twenty six

Explanation:

Hello there!

In this case, according to the molecular formula of the two moles of calcium phosphate:

[tex]2Ca_3(PO_4)_2[/tex]

Thus, in order to calculate the atoms of each atom, it is necessary to multiply the two in front of the formula by the subscripts in the reaction:

[tex]atoms Ca=2*3=6\\\\atoms P=2*2=4\\\\atoms O=2*2*4=16[/tex]

Thus, we obtain six atoms of calcium, four of phosphorous and sixteen of oxygen for a total of twenty six.

Best regards!

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