Answer:
Elastic potential energy E = 0.5 J
Explanation:
Let us assume we have to find the elastic potential energy stored in the spring.
Given: k = 100
change in the length of the spring x = 0.2-0.1 = 0.1 m
Elastic potential energy
E = [tex]\frac{1}{2} kx^2[/tex]
plugging the values we get
[tex]E = 0.5\times100\times0.1^2\\=0.5 J[/tex]
Hence, Elastic potential energy E = 0.5 J
