Answer:
See Explanation
Step-by-step explanation:
Given
New function: [tex]y = 3 \cos(10 (x -\pi))[/tex]
We can assume the parent function to be:
[tex]y = \cos (x)[/tex]
The new function can be represented as:
[tex]y = A*\cos((\frac{2\pi}{B})(x-c))[/tex]
Where
A = Vertical stretch factor
B = Period
C = Right shift
By comparison:
[tex]y = A*\cos((\frac{2\pi}{B})(x-c))[/tex] to [tex]y = 3 \cos(10 (x -\pi))[/tex]
[tex]A = 3[/tex]
[tex]c = \pi[/tex]
[tex]\frac{2\pi}{B} = 10[/tex]
Solve for B
[tex]B = \frac{2\pi}{10}[/tex]
[tex]B = \frac{\pi}{5}[/tex]
Using the calculated values of [tex]A,\ B\ and\ c.[/tex] This implies that, the following transformations occur on the parent function:
- Vertically stretched by [tex]3[/tex]
- Horizontally compressed by [tex]\frac{\pi}{5}[/tex]
- Right shifted by [tex]\pi[/tex]
