martsariayuindeli
martsariayuindeli
19-11-2016
Mathematics
contestada
SOLVE.. 2 cos 3x - 1 = 0
Respuesta :
Аноним
Аноним
19-11-2016
2cos 3x-1=0
2cos 3x=1
cos 3x=1/2
3x=cos⁻¹ 1/2 (cos⁻¹ (1/2)= π/3 + 2Kπ) and cos⁻¹(1/2)=5π/3+2kπ
1)
3x=π/3+2kπ
x=π/9+2/3(kπ) K∈Z; K=...-2,-1,0,1,2...
2)
3x=5π/3+2kπ
x=5π/9+(2/3)kπ
Answer:
x=π/9+2/3(kπ) U 5π/9+(2/3)kπ ; K∈Z
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