Answer:The value of [tex][OH^-][/tex] is [tex]1\time 10^{-11} M[/tex]
Explanation;
The relation of ph and pOh is given as:
pH+pOH=14
pOH = 14 - 3 = 11
The pOH is defined as negative logarithm of hydroxide ion concentration.
[tex]11=-\log[OH^-][/tex]
[tex][OH^-]=1\times ^{-11}[/tex]
The value of [tex][OH^-][/tex] is [tex]1\time 10^{-11} M[/tex]
