A high diver jumps from a 12-meter springboard. The height in meters above the water in seconds, t, is given by the equation, h(t)=−6.1t2+7t+12. At what time does the diver hit the water? Round to the nearest hundredth.

Respuesta :

-6.1t^2+7t+12 plug in graphing calculator and find the zero. It’s slightly less than 2