Answer:
[tex](a)[/tex] [tex]Length= 3cm[/tex] [tex]Width = 6cm[/tex] [tex]Area = 24cm^2[/tex]
[tex](b)[/tex] [tex]Length= 3cm[/tex] [tex]Width = 8cm[/tex] [tex]Area= 24cm^2[/tex]
Step-by-step explanation:
Given
See attachment for rectangle
Solving (a):
From the first rectangle, there are 6 columns and 3 rows.
This implies that:
[tex]Length= 3cm[/tex]
[tex]Width = 6cm[/tex]
So, the area is:
[tex]Area = Length * Width[/tex]
[tex]Area = 3cm * 6cm[/tex]
[tex]Area = 18cm^2[/tex]
Solving (a):
From the first rectangle, there are 3 rows and the total area is 24.
This implies that:
[tex]Length= 3cm[/tex]
[tex]Area= 24cm^2[/tex]
Area is:
[tex]Area = Length * Width[/tex]
[tex]24cm^2= 3cm * Width[/tex]
Make Width the subject
[tex]Width = \frac{24cm^2}{3cm}[/tex]
[tex]Width = 8cm[/tex]
