Respuesta :
Answer:
A. 0.005 = 0.5% probability that the parcel went via El and was late
B. 0.027 = 2.7% probability that a randomly selected parcel arrived late.
C. 0.8148 = 81.48% probability that is was not sent via E1
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
A. If a record of an overnight mailing is randomly selected from the company's file, what is the probability that the parcel went via El and was late?
50% are chosen via E1, and of those, 1% were late. So
[tex]p = 0.5*0.01 = 0.005[/tex]
0.005 = 0.5% probability that the parcel went via El and was late
B. What is the probability that a randomly selected parcel arrived late?
1% of 50%(via E1)
2% of 10%(via E2)
5% of 40%(via E3).
So
[tex]p = 0.01*0.5 + 0.02*0.1 + 0.05*0.4 = 0.027[/tex]
0.027 = 2.7% probability that a randomly selected parcel arrived late.
C. If a randomly selected parcel has arrived on time, what is the probability that is was not sent via E1?
Conditional Probability.
Event A: Late
Event B: Not sent via E1
0.027 = 2.7% probability that a randomly selected parcel arrived late, which means that [tex]P(A) = 0.027[/tex]
Late and not sent via E1:
2% of 10%(via E2)
5% of 40%(via E3).
So
[tex]P(A \cap B) = 0.02*0.1 + 0.05*0.4 = 0.022[/tex]
Desired probability:
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.022}{0.027} = 0.8148[/tex]
0.8148 = 81.48% probability that is was not sent via E1