Respuesta :
Answer: A. [tex]LiN_3[/tex] : Lithium (I) nitride.
B. [tex]Ga_2O_3[/tex] : Galium (III) oxide.
C. [tex]RbCl[/tex]: Rubidium (I) chloride.
D. [tex]BaS[/tex] : Barium (II) sulphide.
Explanation:
Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.
A. Here metal Li is having an oxidation state of +1 called as [tex]Li^{+}[/tex] cation and [tex]N^{3-}[/tex] is an anion with oxidation state of -3. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral [tex]LiN_3[/tex]. The name of the compound is Lithium (I) nitride.
B. Here metal Ga is having an oxidation state of +3 called as [tex]Ga^{3+}[/tex] cation and [tex]O^{2-}[/tex] is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral [tex]Ga_2O_3[/tex]. The name of the compound is Galium (III) oxide.
C. Here metal Rb is having an oxidation state of +1 called as [tex]Rb^{+}[/tex] cation and [tex]Cl^{-}[/tex] is an anion with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral [tex]RbCl[/tex]. The name of the compound is Rubidium (I) chloride.
D. Here metal Ba is having an oxidation state of +2 called as [tex]Ba^{+}[/tex] cation and [tex]S^{2-}[/tex] is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral [tex]BaS[/tex]. The name of the compound is Barium (II) sulphide.
