Answer:
(A) The period of its rotation is 0.5 s (2) The frequency of its rotation is 2 Hz.
Explanation:
Given that,
a ball is spun around in circular motion such that it completes 50 rotations in 25 s.
(1). Let T be the period of its rotation. It can be calculated as follows :
[tex]T=\dfrac{25}{50}\\\\T=0.5\ s[/tex]
(2). Let f be the frequency of its rotation. It can be defined as the number of rotations per unit time. So,
[tex]f=\dfrac{50}{25}\\\\f=2\ Hz[/tex]
Hence, this is the required solution.
