Answer:
The correct answer would be -
RGCB daughter - 0%
RGCB sons - 100%
Explanation:
Red-green color blindness is a sex-linked recessive disease that means it will only express in absence of the normal allele that is present on X-chromosomes. As it is known that males have only one X-chromosomes therefore, the chances are more in males to be affected in presence of the recessive gene. In this given case women s RGCB and man has normal vision. The genotype of women would be both recessive alleles XcXc and genotype of man would be XY.
The gametes would be - Xc, Xc and X, Y
then the cross:
Xc Xc
X XXc XXc
Y XcY XcY
so the offspring would be -
Carrier female = XXc (50% chance in total and 100% in daughters)
RGCB daughters = 0%
RGCB male = XcY (100% in sons and 50% of total children)
