anewton8 anewton8

19-03-2021
Mathematics

contestada

[tex]8x^2+16x+8 [/tex]
Find the real/complex root of 8x^2+16+8

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Berra2008 Berra2008

19-03-2021

I’m pretty sure it is -1 but I might be wrong so, correct me if I am

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surjithayer10otahza surjithayer10otahza

19-03-2021

Answer:

real root =-1 (repeated)

Step-by-step explanation:

8x²+16x+8

8(x²+2x+1)

8(x+1)²=0

x=-1,-1

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