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Answer:
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Explanation:
When the complex ion Co(H2O)6 2+(aq) is placed in solution and chloride ions are added, the following equilobrium is set up;
Co(H2O)62+(aq) + 4 Cl-(aq) <=> CoCl42-(aq) + 6 H2O(g)
Co(H2O)6 2+(aq) solution is pink in colour while CoCl42-(aq) solution is blue in colour.
Since the solubility of CoCl42-(aq) is endothermic, heating the solution will move the equilibrium position towards the right (more CoCl42-(aq) is formed and the solution is blue in colour).
When the solution is cooled, more Co(H2O)62+(aq) is formed and the equilibrium position shifts towards the left and the solution becomes pink in colour.
When the solution is cooled, more [tex]Co(H_2O)_6^{2+}[/tex] (aq) is formed and the equilibrium position shifts towards the left and the solution becomes pink in color.
Balanced equation for the equilibrium:
When the complex ion [tex]Co(H_2O)_6^{2+}[/tex] (aq) is placed in solution and [tex]CoCl_4^{2-}[/tex] are added, the following equilibrium is set up;
[tex]Co(H_2O)_6^{2+}(aq) + 4 Cl^-(aq) < = > CoCl_4^{2-}(aq) + 6 H_2O(g)[/tex]
[tex]Co(H_2O)_6^{2+}[/tex] (aq) solution is pink in color while [tex]CoCl_4^{2-}[/tex](aq) solution is blue in color. Since the solubility of [tex]CoCl_4^{2-}[/tex](aq) is endothermic, heating the solution will move the equilibrium position towards the right (more [tex]CoCl_4^{2-}[/tex] (aq) is formed and the solution is blue in color). When the solution is cooled, more [tex]Co(H_2O)_6^{2+}[/tex] (aq) is formed and the equilibrium position shifts towards the left and the solution becomes pink in color.
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