PLEASE HELP ME WITH THIS MATH!!! In still water, Boat A travels 20km/hr and Boat B travels 25km/hr. Boat A travels 4 hours upstream against the current. Boat B travels 2 hours downstream with the current. Boat A travels 10 km further than Boat B.
Determine 2 equations that could be used to solve for the speed of current "c"
and "d" the distance traveled by Boat A. Then determine the distance Boat A travels.
rate against current is r-c rate with current is r+c a goes agains b goes with a rate=20-c ar=20-c b rate=25+c br=25+c
so
ad=bd+10
ad=ar*at ad=(20-c)(4)
bd=br*bt bd=(25+c)(2) sub
(20-c)(4)=(25+c)(2)+10 divide both sides by 2 (20-c)(2)=(25+c)+5 distribute 40-2c=25+c+5 40-2c=30+c minus 30 both sides 10-2c=c add 2c both sides 10=3c divide both sides by 3 3.3333=c
