Respuesta :
Answer:
We have,:
A=80+B
A=120+C
A+B+C=820
It is a system of equations so:
80+B=120+C
B=40+C
120+C+40+C+C=820
3C=820-160
3C=660
C=220
C=220A=120+220=340
C=220A=120+220=340B=340-80=260
Answer:
We have,:
A=80+B
A=120+C
A+B+C=820
It is a system of equations so:
80+B=120+C
B=40+C
120+C+40+C+C=820
3C=820-160
3C=660
C=220
C=220A=120+220=340
C=220A=120+220=340B=340-80=260