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Find three consecutive odd integers, such that five more than the smallest integer is equal to 25 less than 3 times the largest number. Show work

Respuesta :

Jisallyouget
Let x be the smallest number and y be the largest number.
3y-25-5= x
x+4=y


3(4+x)-25-5= x
12+3x-25-5= x   
        3x-x=-12+25+5
          2x/2= 18/2. 
              X= 9
x+4=y
(9)+4=y
13.    =y

The second number is 11.




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