Respuesta :

timo86

Answer:

B. 64

Step-by-step explanation:

Note that [tex]a^{-n}[/tex] = [tex]\frac{1}{a^{n} }[/tex]. Therefore

[tex](2w^{-2} )^{3} * (8w^{6} )[/tex] = [tex]8w^{-6}[/tex] * [tex]8w^{6}[/tex] = 8 * [tex]\frac{1}{w^{6} }[/tex] * 8 * [tex]w^{6}[/tex] =  8 * 8 * [tex]\frac{w^{6} }{w^{6} }[/tex] = 8 * 8 * 1 8 * 8 = 64