Answer:
MM = 182.13g/mol
Explanation:
Hello!
In this case, since the boiling point elevation is computed via:
[tex]\Delta Tb=i*m*K[/tex]
Thus, since adrenaline is nonionizing, we can compute the molality at first instance:
[tex]m=\frac{\Delta Tb}{i*K}=\frac{0.49K}{1*5.02kg\frac{K}{mol} } \\\\m=0.0976mol/kg[/tex]
Now, we compute the the moles of adrenaline in 360 g (0.360 kg) of CCl4:
[tex]n=0.0976mol/kg*0.360kg\\\\n=0.0351mol[/tex]
Finally, the molar mass:
[tex]MM=\frac{6.4g}{0.0351mol}\\\\MM=182.13g/mol[/tex]
Best regards!
