Answer:
The correct answer is "2524 W".
Explanation:
The given values are:
Ia = 20 A
Ea = 103 V
Ra = 0.19 Ω
La = 4 mH
According to KVL,
⇒ [tex]V_0=E_a-I_aR_a[/tex]
On substituting the given values in the above equation, we get
⇒ [tex]=103-(20)(0.19)[/tex]
⇒ [tex]=103-3.8[/tex]
⇒ [tex]=126.2 \ V[/tex]
Now,[tex]=126.2\times 20[/tex]
The average power flow into the converter will be:
⇒ [tex]P=V_0 I_a[/tex]
On substituting the given values, we get
⇒ [tex]=(126.2\times 20)[/tex]
⇒ [tex]=2524 \ W[/tex]