Bonnie has 4 sharpened and 8 unsharpened pencils in her pencil case. She randomly selects 2 of the pebcils from the box without replacement. What is the probability that both pencils will be sharpened? A. 1/2 B.1/9 C. 4/33 D.1/11

Respuesta :

Answer:

D. 1/11.

Step-by-step explanation:

There are 12 pencils in the case.

Prob( first one is sharpened) = 4/12 = 1/3

Prob(second is sharpened) = 3/11

Prob(both sharpened) = 1/3 * 3/11

= 3/33

= 1/11.

The probability is 1/11 that both pencils will be sharpened which is the correct option(D).

What is probability?

The probability is defined as the possibility of an event being equal to the ratio of the number of outcomes and the total number of outcomes.

Given that,

Bonnie has 4 sharpened and 8 unsharpened pencils

So, there is a total of 12 pencils in the pencil case.

Let, the probability first one is sharpened is P(E₁)

The probability second one is sharpened is P(E₂)

P(E₁) = 4/12 = 1/3

P(E₂) = 3/11

Required probability both sharpened P(E) = P(E₁)×P(E₂)

Required probability both sharpened P(E) = 1/3 × 3/11

Required probability both sharpened P(E) = 3/33

Required probability both sharpened P(E) = 1/11.

Hence, the probability is 1/11 that both pencils will be sharpened.

Learn more about probability here:

brainly.com/question/11234923

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