Answer:
6.576 g NaCl
Explanation:
2Na + Cl2 --> 2 NaCl
Step 1: Find out moles of Na and Cl to determine the limiting reactant:
moles Na = 12/23 = 0.52 moles Na
moles Cl2 = 16/71=0.225 moles Cl2
ratio Na:Cl is 2.3:1 so Cl is the limiting reactant.
Step 2: How many moles of NaCl are formed:
moles NaCl = moles Cl2 x (1 mol NaCl/2 moles Cl2) = 0.225/2 = 0.1125 moles NaCl
Step 3:
mass NaCl = moles NaCl x MM NaCl = 0.1125 x 58.45 = 6.576 g NaCl
