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At what temperature in Kelvin will 0.1243 moles of fluorine exert a pressure of 2.02 atm at a volume of
0.625 L? Answer: 124K
How do I solve this?

Respuesta :

Answer:

Explanation:

The formula would be PV=nRT but since were trying to find temp. the formula becomes T=PV/nR (n is the # moles and R is the ideal gas constant which equals 0.0821 for this)

The formula becomes T= 2.02 x 0.625 divided by 0.1243 x 0.0821 then just solve that in the calculator and u get 123.7K or 124K

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