Answer:
29.9 g of CO₂ will be produced by the reaction.
Explanation:
This is the reaction:
CaCO₃(s) + 2HCl (aq) → CaCl₂(aq) + CO₂(g) + H₂O(l)
First of all, we state the moles of each reactant:
68.1 g . 1mol/ 100.08g = 0.680 mol of carbonate
51.6 g . 1 mol/36.45g = 1.46 mol of acid.
The solid salt is the limiting reactant. Ratio is 2:1
2 moles of acid can react to 1 mol of salt
1.46 mol of acid may react with (1.46 . 1)/2 = 0.727 moles
As we only have 0.680 moles of salt, we do not have enough.
Let's work at the product side. Ratio is 1:1
1 mo of salt can produce 1 mol of gas
0.680 moles will produce 0.680 moles of gas
We convert the moles to mass → 0.680 mol . 44g / 1mol = 29.9 g of CO₂
The number of grams of Co2 should be produced is 29.9 g.
Since
CaCO₃(s) + 2HCl (aq) → CaCl₂(aq) + CO₂(g) + H₂O(l)
So,
68.1 g . 1mol/ 100.08g = 0.680 mol of carbonate
51.6 g . 1 mol/36.45g = 1.46 mol of acid.
Now the ratio should be 2:1 for the solid salt
And, there is 2 moles of acid can react to 1 mol of salt
So,
1.46 mol of acid may react with (1.46 . 1)/2 = 0.727 moles
Now the product side the ratio is 1:1
So, that means
1 mo of salt can produce 1 mol of gas
So, the no of grams should be
= 0.680 mol . 44g / 1mol
= 29.9 g of CO₂
Learn more about grams here: https://brainly.com/question/10623774
