Answer:
2[tex]x^{2}[/tex] + 9x - 5 = 0
Step-by-step explanation:
// Use the Vijet's theorem,
// note that the kofficient before [tex]x^{2}[/tex] = 1
Sum of the roots is:
1/2 + (-5) = - 4,5
Product of the roots is:
0,5 * (-5) = - 2,5
Formation of quadratic equation:
[tex]x^{2}[/tex] - (sum of the roots) x + product of the roots = 0
[tex]x^{2}[/tex] - (-4,5) * x + (-2,5) = 0
[tex]x^{2}[/tex] + 4,5x -2,5 = 0
// multiply both sides by 2
2[tex]x^{2}[/tex] + 9x - 5 = 0
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