log(2)10 = log(2)2 +_____

Given:
[tex]\log_210=\log_22+___[/tex]
To find:
The missing value.
Solution:
Let the missing value be x. Then
[tex]\log_210=\log_22+x[/tex]
[tex]\log_210-\log_22=x[/tex]
Using property of logarithm, we get
[tex]\log_2\left(\dfrac{10}{2}\right)=x[/tex] [tex][\because \log \dfrac{a}{b}=\log a - \log b][/tex]
[tex]\log_2\left(5\right)=x[/tex]
Therefore, the missing value is [tex]\log_2\left(5\right)[/tex].