Answer:
[tex]\boxed {\boxed {\sf c \approx 17.0}}[/tex]
Step-by-step explanation:
This is a right triangle because of the small square in the corner. Therefore, we can use the Pythagorean Theorem.
[tex]a^2+b^2=c^2[/tex]
Where a and b are the legs and c is the hypotenuse.
In this triangle, 11 and 13 are the legs because they make up the right angle. The missing side is the hypotenuse because it is opposite the right angle.
[tex]a=11\\b= 13[/tex]
[tex](11)^2+(13)^2=c^2[/tex]
Solve the exponents.
- 11²= 11*11=121
- 13²= 13*13=169
[tex]121+169=c^2[/tex]
Add.
[tex]289=c^2[/tex]
We are trying to solve for c, so we must isolate the variable. It is being squared. The inverse of a square is the square root, so take the square root of both sides.
[tex]\sqrt {289}= \sqrt {c^2}[/tex]
[tex]17.0293864=c[/tex]
Round to the nearest tenth. The 2 in the hundredth place tells us to leave the 0 in the tenth place.
[tex]17.0 \approx c[/tex]
The missing side is approximately 17.0
