The triangles below are similar... find x. plz helpppp!! :)

Answer:
[tex] x = 11 [/tex]
Step-by-step explanation:
Since they are similar, their correspomding side lengths are proportional to each other. Thus:
[tex] \frac{3x + 3}{x + 7} = \frac{38}{19} [/tex]
[tex] \frac{3x + 3}{x + 7} = 2 [/tex]
Cross multiply
[tex] 3x + 3 = 2(x + 7) [/tex]
[tex] 3x + 3 = 2x + 14 [/tex]
Collect like terms
[tex] 3x - 2x = -3 + 14 [/tex]
[tex] x = 11 [/tex]